TS EAMCET · Physics · Thermal Properties of Matter
The heat energy required convert \(10 \mathrm{~kg}\) of ice at \(-10^{\circ} \mathrm{C}\) into water at \(0^{\circ} \mathrm{C}\) is (specific heat capacity of ice \(=0.5 \mathrm{cal}\) \(\mathrm{g}^{-1}\) and latent heat of fusion of ice \(=80 \mathrm{cal} \mathrm{g}^{-1}\) )
- A \(357 \times 10^4 \mathrm{~J}\)
- B \(357 \times 10^3 \mathrm{~J}\)
- C \(357 \times 10^2 \mathrm{~J}\)
- D \(357 \times 10^5 \mathrm{~J}\)
Answer & Solution
Correct Answer
(A) \(357 \times 10^4 \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
Mass of ice, \(\mathrm{m}=10 \mathrm{~kg}\) Specific heat capacity of ices \(=0.5 \mathrm{cal} \mathrm{g}^{-1}\) \(=2093.4 \mathrm{Joule} / \mathrm{kg}\) Latent heat of fusion of ice, \(\mathrm{L}=80 \mathrm{cal} \mathrm{g}^{-1}\) \(=334944 \mathrm{~J} / \mathrm{kg}\)…
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