TS EAMCET · Physics · Semiconductors
The concentration of electrons in an intrinsic semiconductor is \(6 \times 10^{15} \mathrm{~m}^{-3}\). On doping with an impurity the electron concentration increases to \(4 \times 10^{22}\) \(\mathrm{m}^{-3}\). In thermal equilibrium, the concentration of the holes in the doped semiconductor is
- A \(18 \times 10^{-8} \mathrm{~m}^{-3}\)
- B \(1.5 \times 10^{-7} \mathrm{~m}^{-3}\)
- C \(9 \times 10^8 \mathrm{~m}^{-3}\)
- D \(\frac{2}{3} \times 10^7 \mathrm{~m}^{-3}\)
Answer & Solution
Correct Answer
(C) \(9 \times 10^8 \mathrm{~m}^{-3}\)
Step-by-step Solution
Detailed explanation
using \(n_i^2=n_e n_h\) Given \(n_i=6 \times 10^{15} m^{-3}\),…
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