TS EAMCET · Physics · Thermal Properties of Matter
A composite slab is prepared with two different materials \(A\) and \(B\). The relation between their coefficient of thermal conductivity and thickness is given as \(K_A=\frac{K_B}{2}\) and \(X_A=2 X_B\), respectively. If the temperature of faces of \(A\) and \(B\) are \(75^{\circ} \mathrm{C}\) and \(50^{\circ} \mathrm{C}\) respectively, what will be the temperature of common surface?
- A \(75^{\circ} \mathrm{C}\)
- B \(50^{\circ} \mathrm{C}\)
- C \(55^{\circ} \mathrm{C}\)
- D \(125^{\circ} \mathrm{C}\)
Answer & Solution
Correct Answer
(C) \(55^{\circ} \mathrm{C}\)
Step-by-step Solution
Detailed explanation
The given situation is shown below In steady state, heat flow rate through \(A\) and \(B\) must be equal. If \(T=\) temperature of common surface, then…
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