TS EAMCET · Physics · Gravitation
The energy required to take a body from the surface of the earth to a height equal to the radius of the earth is ' \(W\) '. The energy required to take this body from the surface of the earth to a height equal to twice the radius of the earth is
- A \(\frac{W}{3}\)
- B \(\frac{2 W}{3}\)
- C \(W\)
- D \(\frac{4 W}{3}\)
Answer & Solution
Correct Answer
(D) \(\frac{4 W}{3}\)
Step-by-step Solution
Detailed explanation
Acceleration due to gravity \(g\) varies with height as \(g^{\prime}=g\left(\frac{R}{R+h}\right)\) Acceleration due to gravity at a height equal to the radius of the earth \(g^{\prime}=g\left(\frac{R}{R+R}\right)=\frac{g}{2}\) Acceleration due to gravity at a height equal to…
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