TS EAMCET · Physics · Nuclear Physics
Half-life of a radioactive substance A is two times the half-life of another radioactive substance \(B\). Initially the number of nuclei of \(A\) and \(B\) are \(N_A\) and \(N_B\) respectively. After three half-lives of \(A\), the number of nuclei of both are equal. Then \(\frac{\mathrm{N}_{\mathrm{A}}}{\mathrm{N}_{\mathrm{B}}}\) is
- A \(\frac{1}{3}\)
- B \(\frac{1}{4}\)
- C \(\frac{1}{6}\)
- D \(\frac{1}{8}\)
Answer & Solution
Correct Answer
(D) \(\frac{1}{8}\)
Step-by-step Solution
Detailed explanation
Half, life of a radioactive substance A is two times the half-life of another radioactive substance B. Therefore three half-lives of \(\mathrm{A}\) is equivalent to six half-lives of \(\mathrm{B}\).…
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