TS EAMCET · Physics · Mechanical Properties of Solids
The average depth of an oil well is \(2000 \mathrm{~m}\). If the bulk modulus of oil is \(8 \times 10^8 \mathrm{~N} / \mathrm{m}^2\) and the density of oil is \(1500 \mathrm{~kg} / \mathrm{m}^3\). The fractional compression at the bottom of the well is (take, \(g=10 \mathrm{~m} / \mathrm{s}^2\) )
- A \(3.75 \%\)
- B \(1.75 \%\)
- C \(2.75 \%\)
- D \(4.75 \%\)
Answer & Solution
Correct Answer
(A) \(3.75 \%\)
Step-by-step Solution
Detailed explanation
Bulk modulus is given by \(B=\frac{-p V}{\Delta V} \Rightarrow \frac{-\Delta V}{V}=\frac{p}{B}\) So, fractional compression (in \(\%\) ) is \(-\frac{\Delta V}{V} \times 100=\frac{p}{B} \times 100=\frac{\rho g h}{B} \times 100\) \([\because\) where, \(p=\) pressure \(=\rho g h]\)…
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