TS EAMCET · Physics · Motion In One Dimension
Particle A (which was located at the origin at time \(t=0\) ) is moving along the \(\mathrm{x}\)-axis with a constant speed of \(1 \mathrm{~m} / \mathrm{s}\). Location of particle \(\mathrm{B}\) which is moving along the \(\mathrm{y}\)-axis is given by \(\mathrm{y}=\mathrm{ct}^2\), where \(\mathrm{c}=1 \mathrm{~m} / \mathrm{s}^2\). Find the speed of particle A relative to particle \(\mathrm{B}\) at \(\mathrm{t}=1 \mathrm{sec}\).
- A \(\sqrt{5} \mathrm{~m} / \mathrm{s}\)
- B \(2 \mathrm{~m} / \mathrm{s}\)
- C \(1 \mathrm{~m} / \mathrm{s}\)
- D \(0 \mathrm{~m} / \mathrm{s}\)
Answer & Solution
Correct Answer
(A) \(\sqrt{5} \mathrm{~m} / \mathrm{s}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { For particle along y-axis } \\ & \mathrm{y}=\mathrm{ct}^2 \\ & \Rightarrow \frac{\mathrm{dy}}{\mathrm{dt}}=2 \mathrm{ct} \\ & \Rightarrow \mathrm{V}_{\mathrm{B}}=2 \mathrm{ct} \\ & \text { at } \mathrm{t}=1 \mathrm{sec}, \\ &…
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