TS EAMCET · Physics · Magnetic Effects of Current
A current carrying loop is placed in a uniform magnetic field 'B' in different orientations I, II, III and IV as shown in the figure. The correct order of decreasing potential energy is ( \(\hat{\mathrm{n}}\)-unit vector normal to the plane of the loop)
- A I, III, II, IV
- B I, II, III, IV
- C I, IV, II, III
- D III, IV, I, II
Answer & Solution
Correct Answer
(C) I, IV, II, III
Step-by-step Solution
Detailed explanation
Potential energy in a uniform magnetic field, \(\mathrm{u}=-\mathrm{mB} \cos \theta\) (i) For orientation I \(\theta=180^{\circ} \therefore \mathrm{u}=-\mathrm{mB} \cos 180^{\circ}=\) \(\mathrm{mB}\) (ii) For orientation II…
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