TS EAMCET · Physics · Magnetic Effects of Current
As shown in the figure, a uniform straight wire of length \(30 \sqrt{3} \mathrm{~cm}\) is bent in the form of an equilateral triangle ABC. A uniform magnetic field 2 T is applied parallel to the side BC. If the current through the wire is 2 A, the magnitude of the force on the side AC is
( \(\overline{\mathrm{B}}\) represents the direction of the magnetic field)
- A \(2 \sqrt{3} \mathrm{~N}\)
- B \(0.2 \sqrt{3} \mathrm{~N}\)
- C 1.2 N
- D 0.6 N
Answer & Solution
Correct Answer
(D) 0.6 N
Step-by-step Solution
Detailed explanation
\(L_{side} = \frac{30 \sqrt{3}}{3} \mathrm{~cm} = 10 \sqrt{3} \times 10^{-2} \mathrm{~m}\) \(\theta = 60^\circ\) \(F_{AC} = I L_{side} B \sin \theta\) \(F_{AC} = (2 \mathrm{~A}) (10 \sqrt{3} \times 10^{-2} \mathrm{~m}) (2 \mathrm{~T}) \sin(60^\circ)\)…
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