TS EAMCET · Physics · Magnetic Effects of Current
A dielectric circular disc of radíus \(R\) carries a unform surface charge density \(\sigma\). If it rotates about its axis with angular velocity \(\omega\), the magnetic fíeld at the cente of dísc is :
- A \(\frac{\mu_0 \sigma \omega R^2}{2 \pi}\)
- B \(\frac{\mu_0 \sigma \omega R}{2}\)
- C \(\frac{\mu_0 \sigma \omega R^2}{4}\)
- D \(\frac{\mu_0 \sigma \omega R^2}{2 \sqrt{2}}\)
Answer & Solution
Correct Answer
(B) \(\frac{\mu_0 \sigma \omega R}{2}\)
Step-by-step Solution
Detailed explanation
Let us assumed a ring like element of the disc of radius \(r\) and thickness \(d r\). If \(\sigma\) is the surface charge density, then the charge on the element. \( d q=\sigma(2 \pi r) d r \) Current \(d i\) associated with rotating charge \(d q\) is…
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