TS EAMCET · Physics · Capacitance
If half of the space between the plates of a parallel plate capacitor is filled with a medium of dielectric constant 4 , the capacitance is \(C_1\). If one third of the space between the plates of the capacitor is filled with the medium of dielectric constant 4 , the capacitance is \(C_2\). If in both cases, the dielectric is placed parallel to the plate of the capacitor, then \(C_1: C_2=\)
- A \(2: 3\)
- B \(4: 3\)
- C \(6: 5\)
- D \(7: 5\)
Answer & Solution
Correct Answer
(C) \(6: 5\)
Step-by-step Solution
Detailed explanation
Capacitance of capacitor when dielectric of thickness t and dielectric constant \(K\) is placed between plates \(C=\frac{\epsilon_0 A}{d-t+\frac{t}{K}}\) In first case. \(C_1=\frac{\epsilon_0 A}{d-d / 2+\frac{d}{8}}=\frac{8 \epsilon_0 A}{5 d}\) In second case…
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