TS EAMCET · Physics · Motion In One Dimension
A ball is thrown straight upward from ground with a speed of \(20 \mathrm{~m} / \mathrm{s}\). The ball was caught on its way down at a point \(5 \mathrm{~m}\) above the ground. The time taken by the ball during entire trip is (assume, \(g=10 \mathrm{~m} / \mathrm{s}^2\) )
- A \(2+\sqrt{3} s\)
- B \(3-\sqrt{3} s\)
- C \(2+\sqrt{2} s\)
- D \(3.5 \mathrm{~s}\)
Answer & Solution
Correct Answer
(A) \(2+\sqrt{3} s\)
Step-by-step Solution
Detailed explanation
The given situation of entire motion of ball is shown in the following figure. Initial speed of ball, \(u=20 \mathrm{~m} / \mathrm{s}\) Total time taken by the ball to reach at highest point \(P\) is \(t_1\), then from equation of vertical motion…
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