TS EAMCET · Physics · Mechanical Properties of Fluids
A meniscus drop of radius \(1 \mathrm{~cm}\) is sprayed into \(10^6\) droplets of equal size. Calculate the energy expended if surface tension of mercury is \(435 \times 10^{-3} \mathrm{~N} / \mathrm{m}\).
- A \(54.1 \times 10^{-3} \mathrm{~J}\)
- B \(64.1 \times 10^{-3} \mathrm{~J}\)
- C \(74.1 \times 10^{-3} \mathrm{~J}\)
- D \(84.1 \times 10^{-3} \mathrm{~J}\)
Answer & Solution
Correct Answer
(A) \(54.1 \times 10^{-3} \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
Radius of meniscus, \(R=1 \mathrm{~cm}=10^{-2} \mathrm{~m}\) Number of smaller droplets, \(n=10^6\) Surface tension, \(T=435 \times 10^{-3} \mathrm{Nm}^{-1}\) Work done in splitting a large drop of radius \(R\) in \(n\) smaller drops is \(W=T \times \Delta A\) where,…
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