TS EAMCET · Physics · Thermodynamics
Two identical containers A and B with frictionless pistons contain the same ideal gas at the same temperature and same volume \(\mathrm{V}\). The mass of the gas in \(\mathrm{A}\) is \(\mathrm{m}_{\mathrm{A}}\) and that in \(B\) is \(m_B\). The gas in each cylinder is now allowed to expand isothermally to the same final volume \(2 \mathrm{~V}\). The changes in the pressures of the gases in A and B are found to be \(2 \Delta \mathrm{P}\) and \(3 \Delta \mathrm{P}\) respectively. Then the relation between \(\mathrm{m}_{\mathrm{A}}\) and \(\mathrm{m}_{\mathrm{B}}\) is
- A \(3 \mathrm{~m}_{\mathrm{A}}=4 \mathrm{~m}_{\mathrm{B}}\)
- B \(3 \mathrm{~m}_{\mathrm{A}}=2 \mathrm{~m}_{\mathrm{B}}\)
- C \(2 \mathrm{~m}_{\mathrm{A}}=3 \mathrm{~m}_{\mathrm{B}}\)
- D \(4 \mathrm{~m}_{\mathrm{A}}=3 \mathrm{~m}_{\mathrm{B}}\)
Answer & Solution
Correct Answer
(B) \(3 \mathrm{~m}_{\mathrm{A}}=2 \mathrm{~m}_{\mathrm{B}}\)
Step-by-step Solution
Detailed explanation
Here process is isothermal So, \(p \propto \frac{1}{V}\) for containers, A…
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