TS EAMCET · Physics · Magnetic Effects of Current
If a bar magnet of moment \(10^{-4} \mathrm{Am}^2\) is kept in a uniform magnetic field of \(12 \times 10^{-3} \mathrm{~T}\) such that it makes an angle of \(30^{\circ}\) with the direction of magnetic field, then the torque acting on the magnet is
- A \(6 \times 10^{-7} \mathrm{Nm}\)
- B \(6 \times 10^{-5} \mathrm{Nm}\)
- C \(12 \times 10^{-7} \mathrm{Nm}\)
- D \(12 \times 10^{-5} \mathrm{Nm}\)
Answer & Solution
Correct Answer
(A) \(6 \times 10^{-7} \mathrm{Nm}\)
Step-by-step Solution
Detailed explanation
Given, Magnet moment of bar magnet, \(\mathrm{m}=10^{-4} \mathrm{Am}^2\) Magnetic field, \(\mathrm{B}=12 \times 10^{-3} \mathrm{~T}\) Torque on the bar magnet \(\mathrm{T}=\mathrm{mB} \sin \theta\)…
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