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TS EAMCET · Physics · Semiconductors

If 5 mg of U235 is completely destroyed in an atom bomb, then approximate total energy released is (given that the energy released per fission is 200 MeV)

  1. A 4×108 J
  2. B 6×109 J
  3. C 5×107 J
  4. D 3×1010 J
Verified Solution

Answer & Solution

Correct Answer

(A) 4×108 J

Step-by-step Solution

Detailed explanation

Number of uranium atom is, N=NA235×5×10-3 ⇒N=6.022×1023235×5×10-3=1.28×1019 To energy in this fission is, E=N×200 MeV ⇒E=1.28×1019×200×106×1.6×10-19 J ⇒E≈4×108 J
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