TS EAMCET · Physics · Wave Optics
Two slits separated by a distance of \(1 \mathrm{~mm}\) are illuminated with light of wavelength \(6.5 \times 10^{-7} \mathrm{~m}\). The interference fringes are observed on a screen placed at \(1 \mathrm{~m}\) from the slits. The distance between the third dark fringe and the fifth bright fringe is equal to
- A \(0.655 \mathrm{~mm}\)
- B \(1.625 \mathrm{~mm}\)
- C \(3.125 \mathrm{~mm}\)
- D \(4.785 \mathrm{~mm}\)
Answer & Solution
Correct Answer
(B) \(1.625 \mathrm{~mm}\)
Step-by-step Solution
Detailed explanation
Distance between two slit, \(\mathrm{d}=1 \mathrm{~mm}=10^{-3} \mathrm{~m}\) Light of wavelength, \(\lambda=6.5 \times 10^{-7} \mathrm{~m}\) Distance of screen from the slit, \(D=1 \mathrm{~m}\) For distance of dark fringe,…
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