TS EAMCET · Physics · Current Electricity
A potentiometer balances at \(44 \mathrm{~cm}\) when a cell of internal resistance \(1 \Omega\) is in the secondary circuit. To obtain the balancing point at \(40 \mathrm{~cm}\), the resistance to be connected parallel to cell is
- A \(20 \Omega\)
- B \(10 \Omega\)
- C \(30 \Omega\)
- D \(5 \Omega\)
Answer & Solution
Correct Answer
(B) \(10 \Omega\)
Step-by-step Solution
Detailed explanation
(b) Internal Resistance, \(\mathrm{r}=1 \Omega\) Balancing Point, \(\ell_1=44 \mathrm{~cm}\). Obtain Balancing Point \(\ell_2=40 \mathrm{~cm}\). Internal Resistance is given by \[ \mathrm{r}=\mathrm{R}\left[\frac{\ell_1-\ell_2}{\ell_2}\right] \]…
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