TS EAMCET · Physics · Current Electricity
Four \(4 \Omega\) resistors are connected together along the edges of a square. A \(12 \mathrm{~V}\) battery with internal resistance of \(2 \Omega\) is connected across a pair of the diagonally opposite corners of the square. The power dissipated in the circuit is
- A \(36 \mathrm{~W}\)
- B \(192 \mathrm{~W}\)
- C \(24 \mathrm{~W}\)
- D \(48 \mathrm{~W}\)
Answer & Solution
Correct Answer
(A) \(36 \mathrm{~W}\)
Step-by-step Solution
Detailed explanation
According to the question, the circuit diagram is as shown below Power dissipated in circuit, \(P=\frac{E^2}{R_{\text {eff }}}\) ...(i) The given circuit is a balanced Wheatstone bridge. So, its equivalent resistance is given by…
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