TS EAMCET · Physics · Laws of Motion
A block rests on a fixed wedge inclined at an angle \(\theta\). The coefficient of friction between the block and plane is \(\mu\). The maximum value of \(\theta\) for the block to remain motionless on the wedge is
- A \(\mu=\tan \theta\)
- B \(\mu=\sin \theta\)
- C \(\mu=\cos \theta\)
- D \(\mu=\cot \theta\)
Answer & Solution
Correct Answer
(A) \(\mu=\tan \theta\)
Step-by-step Solution
Detailed explanation
The given condition can be shown with a proper FBD of the block, as below Let us suppose the mass of the block is \(m\) and acceleration due to gravity is \(g\). Normal reaction, \(N=m g \cos \theta\) Limiting friction, \((f r)_{\lim }=\mu_s N=\mu m g \cos \theta\) Net driving…
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