TS EAMCET · Physics · Current Electricity
A uniform conducting wire \(\mathrm{AB}\) of length \(5 \mathrm{~m}\) and resistance \(5 \Omega\) is connected as shown in the circuit. If the balancing point is obtained at \(3 \mathrm{~m}\) from \(\mathrm{A}\), then the value of \(\mathrm{E}\) is 
- A \(1.5 \mathrm{~V}\)
- B \(3 \mathrm{~V}\)
- C \(0.67 \mathrm{~V}\)
- D \(1.33 \mathrm{~V}\)
Answer & Solution
Correct Answer
(B) \(3 \mathrm{~V}\)
Step-by-step Solution
Detailed explanation
Net resistance of the circuit \(=R=5+4+1\) \(=10 \Omega\) And resistance due to \(3 \mathrm{~m}\) balance length, \(\mathrm{R}^{\prime}=\frac{5}{5} \times 3=3 \Omega\) At balance length, both circuits have equal currents…
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