TS EAMCET · Physics · Magnetic Properties of Matter
A small bar magnet experiences a torque of \(0.016 \mathrm{Nm}\) when placed with its axis at \(30^{\circ}\) with an external field of \(0.04 \mathrm{~T}\). If the bar magnet is replaced by a solenoid of cross-sectional area of \(1 \mathrm{~cm}^2\) and 1000 turns but having the same magnetic moment as that of bar magnet, then the current flowing through the solenoid is
- A \(2 \mathrm{~A}\)
- B \(4 \mathrm{~A}\)
- C \(6 \mathrm{~A}\)
- D \(8 \mathrm{~A}\)
Answer & Solution
Correct Answer
(D) \(8 \mathrm{~A}\)
Step-by-step Solution
Detailed explanation
Given, torque on a bar magnet, \(\tau=0.016 \mathrm{Nm}\), \(\theta=30^{\circ}\) and magnetic field, \(B=0.04 \mathrm{~T}\) Since, \(\tau=m \mathrm{~B} \sin \theta\)…
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