TS EAMCET · Physics · Magnetic Effects of Current
A square coil of side 10 cm having 200 turns is placed in a uniform magnetic field of 2 T such that the plane of the coil is in the direction of magnetic field. If the current through the coil is 3 mA, then the torque acting on the coil is
- A \(12 \times 10^{-3} \mathrm{Nm}\)
- B \(24 \times 10^{-3} \mathrm{Nm}\)
- C \(6 \times 10^{-3} \mathrm{Nm}\)
- D Zero
Answer & Solution
Correct Answer
(A) \(12 \times 10^{-3} \mathrm{Nm}\)
Step-by-step Solution
Detailed explanation
\(A = s^2 = (0.1 \, \mathrm{m})^2 = 0.01 \, \mathrm{m}^2\) \(\tau = NIAB \sin\theta\) \(\tau = (200)(3 \times 10^{-3} \, \mathrm{A})(0.01 \, \mathrm{m}^2)(2 \, \mathrm{T}) \sin(90^\circ)\) \(\tau = (200)(3 \times 10^{-3})(0.01)(2)(1) \, \mathrm{Nm}\)…
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