TS EAMCET · Physics · Work Power Energy
A small disc of mass \(1 \mathrm{~g}\) slides down a smooth hill of height \(10 \mathrm{~m}\) from rest and gets on to a plank of mass \(100 \mathrm{~g}\) as shown in the figure. Due to friction between the disc and the plank. The disc slows down and moves as one piece with the plank. The work done by the frictional force is approximately (Use, \(g=10 \mathrm{~ms}^2\) ) 
- A 0.01 J
- B 10 J
- C 0.1 J
- D 1 J
Answer & Solution
Correct Answer
(C) 0.1 J
Step-by-step Solution
Detailed explanation
The disc is at rest at the top of the hill. \(\therefore\) Potential energy of the disc, \(U=m g h\) Let the velocity of the sliding disc before the friction is \(v\). \(\therefore\) The kinetic energy, \(K=\frac{1}{2} m v^2\) From energy conservation,…
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