TS EAMCET · Physics · Oscillations
A simple harmonic oscillator consists of a particle of mass \(m\) and an ideal spring with spring constant \(k\). The particle oscillates with a time period \(T\). The spring is cut into two equal parts. If one part oscillates with the same particle, the time period will be
- A \(2 T\)
- B \(\sqrt{2} T\)
- C \(\frac{T}{\sqrt{2}}\)
- D \(\frac{T}{2}\)
Answer & Solution
Correct Answer
(C) \(\frac{T}{\sqrt{2}}\)
Step-by-step Solution
Detailed explanation
Mass of the particle \(=m\) spring constant \(=k\) The time period of oscillator, \(T=2 \pi \sqrt{\frac{m}{k}}\) As \(k \propto \frac{1}{l}\) (where \(l\) is the length of spring)…
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