TS EAMCET · Physics · Ray Optics
A short straight object of length \(l\) lies along the central axis of a spherical concave mirror, at a distance \(X\) from the mirror. The focal length of the mirror is \(F\). If the length of the image in the mirror is \(l^{\prime}\), then ratio \(\left(\frac{l^{\prime}}{l}\right)\) is (assume, \(l< < \) and \(l< < F\) )
- A \(\frac{F-X}{F}\)
- B \(\left(\frac{F-X}{F}\right)^2\)
- C \(\left(\frac{F}{F-X}\right)^2\)
- D \(\frac{F}{X}\)
Answer & Solution
Correct Answer
(C) \(\left(\frac{F}{F-X}\right)^2\)
Step-by-step Solution
Detailed explanation
The given situation is shown in the following figure. \(\begin{aligned} & A B \rightarrow \text { object, } A^{\prime} B^{\prime} \rightarrow \text { image } \\ & \qquad A B=l, A^{\prime} B^{\prime}=l^{\prime}, u=-X, \end{aligned}\) Hence, by mirror formula,…
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