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TS EAMCET · Physics · Magnetic Effects of Current

A proton accelerated by a potential difference 500kV flies through a uniform transverse magnetic field 0.1 T. The field is spread on a region of 1.0 cm thickness. The angle through which the proton gets deviated from its original direction is (Proton mass =1.6×10-27 kg and charge of proton=1.6×10-19C )

  1. A 0.01rad
  2. B 0.1rad
  3. C 0.05rad
  4. D 0.08rad
Verified Solution

Answer & Solution

Correct Answer

(A) 0.01rad

Step-by-step Solution

Detailed explanation

The radius of circular path is, R=2mKEqB=2×1.6×10-27×1.6×10-16× 500×1031.6×10-16× 0.1=1 m Since KE=qV For small value of θ and arc of cirlcle, θ=arcR=1×10-21=10-2=0.01 rad
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