TS EAMCET · Physics · Dual Nature of Matter
The de-Broglie wavelength of an electron moving with a velocity of \(1.5 \times 10^8 \mathrm{~m} / \mathrm{s}\) is equal to that of a photon. The ratio of kinetic energy of the electron to that of the photon \(\left(c=3 \times 10^8 \mathrm{~m} / \mathrm{s}\right)\)
- A \(2\)
- B \(4\)
- C \(\frac{1}{2}\)
- D \(\frac{1}{4}\)
Answer & Solution
Correct Answer
(D) \(\frac{1}{4}\)
Step-by-step Solution
Detailed explanation
The ratio of kinetic energy of the electron to that of the photon. \(\begin{aligned} & =\frac{v}{2 c} \\ & =\frac{1.5 \times 10^8}{2 \times 3 \times 10^8}=\frac{1}{4}\end{aligned}\)
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