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TS EAMCET · Physics · Laws of Motion

A bar of mass m resting on a smooth horizontal plane starts moving due to force |F|=mg9. The magnitude of the force remains constant with time. The force vector makes an angle θ with the horizontal which varies with the distance covered as θ=Cx. If the constant C=10  degree meter , then the speed of the bar, when θ becomes equal to 30° for the first time, is (Assume g=10 m s-2)

  1. A 0.33 m s-1
  2. B 0.50 m s-1
  3. C 1.0 m s-1
  4. D 0.8 m s-1
Verified Solution

Answer & Solution

Correct Answer

(A) 0.33 m s-1

Step-by-step Solution

Detailed explanation

Given, The magnitude of a force, |F→|=mg9 and Force vector makes a varying angle θ with the horizontal as θ=Cx, where, C=10 degree meter . Thus, Horizontal component of force, Fx=F cos θ=F cos Cx. Applying work energy…
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