TS EAMCET · Physics · Electromagnetic Induction
Suppose that the electric flux inside a parallel plate capacitor changes at a rate of \(7 \times 10^{14}\) unit/s, then the magnetic induction field density at any point inside the capacitor is [Area of the plate of the capacitor \(=1 \mathrm{~m}^2\) Permittivity of free space \[ =8.8 \times 10^{-12} \mathrm{Nm}^2 \mathrm{C}^{-2} \] Permeability of free space \[ =4 \pi \times 10^{-7} \text { tesla } \mathrm{m} / \mathrm{amp} \]
- A \(2.0 \times 10^{-3} \mathrm{~T}\)
- B \(0.779 \times 10^{-5} \mathrm{~T}\)
- C \(8.85 \times 10^{-4} \mathrm{~T}\)
- D \(88.5 \times 10^{-12} \mathrm{~T}\)
Answer & Solution
Correct Answer
(A) \(2.0 \times 10^{-3} \mathrm{~T}\)
Step-by-step Solution
Detailed explanation
Point where ' \(B\) ' to be calculated is not mentioned. On surface \(\int \mathrm{B} \cdot d \mathrm{l}=\mu_0\left(\varepsilon_0 \frac{d \phi}{d t}\right)\)…
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