TS EAMCET · Physics · Semiconductors
A semiconductor has equal electron and hole concentration of \(2 \times 10^8 \mathrm{~m}^{-3}\). On doping with a certain impurity, the electron concentration increases to \(4 \times 10^{10} \mathrm{~m}^{-3}\), then the new hole concentration of the semiconductor is
- A \(10^6 \mathrm{~m}^3\)
- B \(10^8 \mathrm{~m}^3\)
- C \(10^{10} \mathrm{~m}^3\)
- D \(10^{12} \mathrm{~m}^3\)
Answer & Solution
Correct Answer
(A) \(10^6 \mathrm{~m}^3\)
Step-by-step Solution
Detailed explanation
Electron concentration, \(n_e=2 \times 10^8 \mathrm{~m}^{-3}\) Hole concentration, \(n_h=2 \times 10^8 \mathrm{~m}^{-3}\) After doping with a impurity, the new electron concentration, \(n_e^{\prime}=4 \times 10^{10} \mathrm{~m}^{-3}\) New hole concentration, \(n_h^{\prime}=\) ?…
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