TS EAMCET · Physics · Electrostatics
Four electric charges \(2 \mu \mathrm{C}, \mathrm{Q}, 4 \mu \mathrm{C}\) and \(12 \mu \mathrm{C}\) are placed on \(x\)-axis at distances \(x=0\), \(1 \mathrm{~cm}, 2 \mathrm{~cm}\) and 4 cm respectively. If the net force acting on the charge at origin is zero, then \(\mathrm{Q}=\)
- A \(-3.5 \mu \mathrm{C}\)
- B \(-1.75 \mu \mathrm{C}\)
- C \(-2.75 \mu \mathrm{C}\)
- D \(-5.5 \mu \mathrm{C}\)
Answer & Solution
Correct Answer
(B) \(-1.75 \mu \mathrm{C}\)
Step-by-step Solution
Detailed explanation
\(F_{net} = F_{12} + F_{13} + F_{14} = 0\) \(k \frac{q_1 Q}{r_{12}^2} + k \frac{q_1 q_3}{r_{13}^2} + k \frac{q_1 q_4}{r_{14}^2} = 0\) \(\frac{Q}{(1 \mathrm{~cm})^2} + \frac{4 \mu \mathrm{C}}{(2 \mathrm{~cm})^2} + \frac{12 \mu \mathrm{C}}{(4 \mathrm{~cm})^2} = 0\)…
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