TS EAMCET · Physics · Work Power Energy
A block of mass ' \(m\) ' with an initial kinetic energy ' \(E\) moves up an inclined plane of inclination ' \(\theta\) '. If ' \(\mu\) ' is the coefficient of friction between the plane and the body, the work done against friction before coming to rest is
- A \(\mu E \cos \theta\)
- B \(\frac{\mu E \cos \theta}{\sin \theta-\mu \cos \theta}\)
- C \(\frac{E \mu \cos \theta}{\cos \theta+\sin \theta}\)
- D \(\frac{\mu E \cos \theta}{\sin \theta+\mu \cos \theta}\)
Answer & Solution
Correct Answer
(D) \(\frac{\mu E \cos \theta}{\sin \theta+\mu \cos \theta}\)
Step-by-step Solution
Detailed explanation
Let before coming to rest body slides up to distance s . \(\mathrm{h}=\mathrm{s} \sin \theta\) From the work- energy theorem,…
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