TS EAMCET · Physics · Center of Mass Momentum and Collision
A bomb moving with velocity \((40 \hat{\mathbf{i}}+50 \hat{\mathbf{j}}-25 \hat{\mathbf{k}}) \mathrm{m} / \mathrm{s}\) explodes into two pieces of mass ratio \(1: 4\). After explosion the smaller piece moves away with velocity \((200 \hat{\mathbf{i}}+70 \hat{\mathbf{j}}+15 \hat{\mathbf{k}}) \mathrm{m} / \mathrm{s}\). The velocity of larger piece after explosion is
- A \(45 \hat{\mathbf{j}}-35 \hat{\mathbf{k}}\)
- B \(45 \hat{\mathbf{i}}-35 \hat{\mathbf{j}}\)
- C \(45 \hat{\mathbf{k}}-35 \hat{\mathbf{j}}\)
- D \(-35 \hat{\mathbf{i}}+45 \hat{\mathbf{k}}\)
Answer & Solution
Correct Answer
(A) \(45 \hat{\mathbf{j}}-35 \hat{\mathbf{k}}\)
Step-by-step Solution
Detailed explanation
From conservation of linear momentum \(5 m(40 \hat{\mathbf{i}}+50 \mathbf{j}-25 \hat{\mathbf{k}})\) \(=m(200 \hat{\mathbf{i}}+70 \hat{\mathbf{j}}+15 \hat{\mathbf{k}})+4 m(x \hat{\mathbf{i}}+y \hat{\mathbf{j}}+z \hat{\mathbf{k}})\)…
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