TS EAMCET · Physics · Ray Optics
A beam of light propagating at an angle \(\alpha_1\) from a medium 1 through to another medium 2 at an angle \(\alpha_2\). If the wavelength of light in medium 1 is \(\lambda_1\), then the wavelength of light in medium \(2,\left(\lambda_2\right)\), is
- A \(\frac{\sin \alpha_2}{\sin \alpha_1} \lambda_1\)
- B \(\frac{\sin \alpha_1}{\sin \alpha_2} \lambda_2\)
- C \(\left(\frac{\alpha_1}{\alpha_2}\right) \lambda_4\)
- D \(\lambda_1\)
Answer & Solution
Correct Answer
(A) \(\frac{\sin \alpha_2}{\sin \alpha_1} \lambda_1\)
Step-by-step Solution
Detailed explanation
We know that, \[ \lambda=\frac{\lambda_0}{\mu} \] According to the question, \[ \begin{array}{r} \frac{\sin \alpha_1}{\sin \alpha_2}=\frac{\mu_2}{\mu_1}=\frac{\lambda_1}{\lambda_2} \\ \lambda_2=\lambda_1 \frac{\sin \alpha_2}{\sin \alpha_1} \end{array} \]
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