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TS EAMCET · Physics · Motion In Two Dimensions

A body projected vertically upwards crosses a point twice in its journey at a height \(h\) just after \(t_1\) and \(t_2\) seconds. Maximum height reached by the body is

  1. A \(\frac{g}{4}\left(t_1+t_2\right)^2\)
  2. B \(g\left(\frac{t_1+t_2}{4}\right)^2\)
  3. C \(2 g\left(\frac{t_1+t_2}{4}\right)^2\)
  4. D \(\frac{g}{4}\left(t_1 t_2\right)\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(2 g\left(\frac{t_1+t_2}{4}\right)^2\)

Step-by-step Solution

Detailed explanation

Time taken by the body to reach the point \(A\) is \(t_1\) (During upward journey). The body crosess this point again (during downward journey) after \(t_2\), i.e., the body takes the time \(\left(t_2-t_1\right)\) to come again at point \(A\). So, the time taken by the body to…
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