TS EAMCET · Physics · Kinetic Theory of Gases
At what temperature is the root mean square (rms) speed of Neon gas atoms is equal to the rms speed of Helium gas atom at \(-33^{\circ} \mathrm{C}\) ? (atomic mass of \(\mathrm{Ne}=2.02 \mathrm{u}\), and that of \(\mathrm{He}=4.0 \mathrm{u}\) )
- A 1208 K
- B 1210 K
- C 1212 K
- D 1220 K
Answer & Solution
Correct Answer
(C) 1212 K
Step-by-step Solution
Detailed explanation
\begin{aligned} & \left(\mathrm{V}_{\mathrm{rms}}\right)_{\mathrm{Neon}}=\left(\mathrm{V}_{\mathrm{rms}}\right)_{\mathrm{He}} \\ & \Rightarrow \sqrt{\frac{3 \mathrm{R} \times \mathrm{T}}{20.2}}=\sqrt{\frac{3 \mathrm{R} \times 240}{4}} \\ & \Rightarrow \frac{\mathrm{T}}{20.2}=60…
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