TS EAMCET · Maths · Complex Number
\(x\) and \(y\) are two complex numbers such that \(|x|=|y|=1\). If \(\operatorname{Arg}(x)=2 \alpha, \operatorname{Arg}(y)=3 \beta\) and \(\alpha+\beta=\frac{\pi}{36}\), then \(x^6 y^4+\frac{1}{x^6 y^4}=\)
- A 0
- B -1
- C 1
- D \(\frac{1}{2}\)
Answer & Solution
Correct Answer
(C) 1
Step-by-step Solution
Detailed explanation
\(x=e^{i 2 \alpha}, y=e^{i 3 \beta}\) \(x^6 y^4=e^{12 i(\alpha+\beta)} ; \frac{1}{x^6 y^4}=e^{-12 i(\alpha+\beta)}\)…
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