TS EAMCET · Maths · Circle
If the circle \(x^2+y^2+6 x-2 y+k=0\) bisects the circumference of the circle \(x^2+y^2+2 x-6 y-15=0\), then \(k\) is equal to :
- A 21
- B -21
- C 23
- D -23
Answer & Solution
Correct Answer
(D) -23
Step-by-step Solution
Detailed explanation
Given that, \(S_1 \equiv x^2+y^2+6 x-2 y+k=0\) and \(\quad S_2 \equiv x^2+y^2+2 x-6 y-15=0\) Since, \(S_1\) bisects \(S_2\), then Chord of \(S_2=\) Diameter of \(S_1\) Equation of the chord is \(S_1-S_2=0\) \(\left(x^2+y^2+6 x-2 y+k\right)\)…
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