TS EAMCET · Maths · Properties of Triangles
If \(b+c=3 a\), then \(\cot \frac{B}{2} \cot \frac{C}{2}\) is equal to :
- A 3
- B 1
- C 4
- D 2
Answer & Solution
Correct Answer
(D) 2
Step-by-step Solution
Detailed explanation
\(\cot \frac{B}{2} \cdot \cot \frac{C}{2}\) \(=\sqrt{\frac{s(s-b)}{(s-c)(s-a)}} \times \sqrt{\frac{s(s-c)}{(s-a)(s-b)}}\) \(=\frac{s}{s-a}=\frac{2 a}{2 a-a}=2 \quad(\because b+c=3 a)\)
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