TS EAMCET · Chemistry · Solid State
In a bcc lattice having the edge length of \(200 \mathrm{pm}\), the cation has the radius of \(70 \mathrm{pm}\). The radius ratio of \(\frac{r^{+}}{r^{-}}\)is (Given, \(\sqrt{2}=1.4, \sqrt{3}=1.7\) and \(\sqrt{6}=2.4\) )
- A 0.7
- B 1
- C 0.4
- D 0.2
Answer & Solution
Correct Answer
(A) 0.7
Step-by-step Solution
Detailed explanation
\(\because\) For bcc lattice, radius ratio for \(r^{+} / r^{-}\)is 0.7 , i.e. radius ratio of cation by anion ranges from 0.732 to 1.0. Also, for bcc \(r^{-}\)ions are at corners, Thus, \(4 \times r^{-}=\sqrt{3} a \quad(\because \sqrt{3} a=1.7 \times 200)\) (where, \(a=\) edge…
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