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TS EAMCET · Maths · Complex Number

If \(|Z|=2, Z_1=\frac{Z}{2} e^{i \alpha}\) and \(\theta\) is the \(\operatorname{amp}(Z)\), then \(\frac{Z_1{ }^n-Z_1{ }^{-n}}{Z_1{ }^n+Z_1{ }^{-n}}=\)

  1. A \(2^n i \tan (n \theta+n \alpha)\)
  2. B \(i \tan (n \theta-n \alpha)\)
  3. C \(i \tan (n \theta+n \alpha)\)
  4. D \(\tan (n \theta+n \alpha)\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(i \tan (n \theta+n \alpha)\)

Step-by-step Solution

Detailed explanation

\(Z = |Z|e^{i \theta} = 2e^{i \theta}\) \(Z_1 = \frac{2e^{i \theta}}{2} e^{i \alpha} = e^{i (\theta + \alpha)}\) \(\frac{Z_1{ }^n-Z_1{ }^{-n}}{Z_1{ }^n+Z_1{ }^{-n}} = \frac{e^{in(\theta+\alpha)}-e^{-in(\theta+\alpha)}}{e^{in(\theta+\alpha)}+e^{-in(\theta+\alpha)}}\)…