TS EAMCET · Maths · Straight Lines
When the origin is shifted to the point \(\left(\frac{3}{2}, \frac{3}{2}\right)\) by the translation of coordinate axes, then the transformed equation of \(32 x^2+8 x y+32 y^2-108 x-108 y+99=0\) is
- A \(72 X^2+56 Y^2-63=0\)
- B \(X^2-14 X Y-7 Y^2-2=0\)
- C \(32 X^2-16 X Y+32 Y^2-225=0\)
- D \(32 X^2+8 X Y+32 Y^2-63=0\)
Answer & Solution
Correct Answer
(D) \(32 X^2+8 X Y+32 Y^2-63=0\)
Step-by-step Solution
Detailed explanation
Substituting \(x=X+\frac{3}{2}, y=Y+\frac{3}{2}\) in the equation \(32 x^2+8 x y+32 y^2-108 x-108 y+99=0\), we get…
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