ExamBro
ExamBro
TS EAMCET · Maths · Probability

Keep fixed first position whose possible numbers are 1, \[ \begin{aligned} & 2,3 \text { and } 4 . \ & =1 \times 4+1 \times 4+1 \times 4+1 \times 3=15 . \ & \mathrm{P}(\mathrm{E}) \frac{\text { Favourable }}{\text { Total }}=\frac{15}{36}=\frac{5}{12} \end{aligned} \] So, option (d) is correct.

  1. A \(\frac{94}{663}\)
  2. B \(\frac{62}{663}\)
  3. C \(\frac{30}{663}\)
  4. D \(\frac{64}{663}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{62}{663}\)

Step-by-step Solution

Detailed explanation

Given a well shuffled pack of 52 cards.…
Same subject
Explore more questions on app
From TS EAMCET
Explore more questions on app