TS EAMCET · Maths · Probability
The probability of a coin showing head is \(p\) and then 100 such coins are tossed. If the probability of 50 coins showing head is same as the probability of 51 coins showing head, then \(p\) equals
- A \(\frac{1}{2}\)
- B \(\frac{49}{100}\)
- C \(\frac{51}{101}\)
- D \(\frac{50}{101}\)
Answer & Solution
Correct Answer
(C) \(\frac{51}{101}\)
Step-by-step Solution
Detailed explanation
It is given that probability of showing head is \(p\), then probability of showing tail will be \((1-p)\). Also, probability of showing 50 and 51 heads in tossing a coin 100 times is same.…
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