TS EAMCET · Maths · Probability
Urn A contains 6 white and 2 black balls; urn B contains 5 white and 3 black balls and urn C contains 4 white and 4 black balls. If an urn is chosen at random and a ball is drawn at random from it, then the probability that the ball drawn is white is
- A \(\frac{3}{8}\)
- B \(\frac{5}{8}\)
- C \(\frac{1}{2}\)
- D \(\frac{3}{4}\)
Answer & Solution
Correct Answer
(B) \(\frac{5}{8}\)
Step-by-step Solution
Detailed explanation
\(P(W) = P(W|U_A)P(U_A) + P(W|U_B)P(U_B) + P(W|U_C)P(U_C)\) \(P(W) = \left(\frac{6}{8} \cdot \frac{1}{3}\right) + \left(\frac{5}{8} \cdot \frac{1}{3}\right) + \left(\frac{4}{8} \cdot \frac{1}{3}\right)\) \(P(W) = \frac{1}{3} \left(\frac{6}{8} + \frac{5}{8} + \frac{4}{8}\right)\)…
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