TS EAMCET · Maths · Circle
If \(\alpha\) and \(\beta\) are the roots of \(x^2+2 x-3=0\) and \(\gamma, \delta\) are the roots of \(y^2-y-4=0\), then the equation of the circle having \((\alpha, \gamma)\) and \((\beta, \delta)\) as ends of a diameter is
- A \(x^2+y^2+4 x-3 y+2=0\)
- B \(x^2+y^2+2 x-y+7=0\)
- C \(x^2+y^2-3 x+4 y+1=0\)
- D \(x^2+y^2-2 x+y-1=0\)
Answer & Solution
Correct Answer
(B) \(x^2+y^2+2 x-y+7=0\)
Step-by-step Solution
Detailed explanation
Given, data is incorrect because \(y^2-y+4=0\) has imaginary discriminant and never gives equal to zero.
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