TS EAMCET · Maths · Probability
Two dice are rolled. If a random variable \(X\) denotes the sum of the numbers on them and \(\mu\) denotes the mean of \(X\), then \(\mu+P(X < 5)+P(X>9)+P(x=7)=\)
- A \(\frac{15}{2}\)
- B 17
- C \(\frac{17}{2}\)
- D 15
Answer & Solution
Correct Answer
(A) \(\frac{15}{2}\)
Step-by-step Solution
Detailed explanation
\(X=\) denotes the sum of number when two dice are rolled \( \mu(\text { Mean })=\Sigma P_i X_i=\frac{252}{36}=7 \) Now, \(\mu-p(X < 5)+P(X>9)+p(X=7)\) \( \frac{252}{36}+\frac{6}{36}+\frac{6}{36}+\frac{6}{36}=\frac{270}{36}=\frac{15}{2} \)
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