TS EAMCET · Maths · Area Under Curves
The area of the triangle formed by the positive \(X\)-axis, the tangent and normal to the curve \(x^2+y^2=16 \alpha^2\) at the point \((2 \sqrt{2} a, 2 \sqrt{2} a)\) is
- A \(a^2\)
- B \(16 a^2\)
- C \(4 a^2\)
- D \(8 a^2\)
Answer & Solution
Correct Answer
(D) \(8 a^2\)
Step-by-step Solution
Detailed explanation
Given curve is \( x^2+y^2=16 a^2 \) On differentiating Eq. (i) w.r.t. \(x\), we get…
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