TS EAMCET · Maths · Permutation Combination
There are 10 points in a plane, of which no three points are collinear except 4 . Then, the number of distinct triangles that can be formed by joining any three points of these ten points, such that at least one of the vertices of every triangle formed is from the given 4 collinear points is
- A \(80\)
- B \(100\)
- C \(96\)
- D \(116\)
Answer & Solution
Correct Answer
(C) \(96\)
Step-by-step Solution
Detailed explanation
Number of required triangles: (Select 1 point from 4 collinear and 2 from remaining 6 ) OR (select 2 from collinear points \& 1 from remaining 6 )…
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